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lvzhengyang
riscv-gcc-1
Commits
ef659ec0
Commit
ef659ec0
authored
Jun 26, 1992
by
Tom Wood
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From-SVN: r1301
parent
5a7ec9d9
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152 additions
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5 deletions
+152
-5
gcc/fold-const.c
+152
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gcc/fold-const.c
View file @
ef659ec0
...
@@ -2304,7 +2304,125 @@ all_ones_mask_p (mask, size)
...
@@ -2304,7 +2304,125 @@ all_ones_mask_p (mask, size)
size_int
(
precision
-
size
)),
0
);
size_int
(
precision
-
size
)),
0
);
}
}
/* Try to optimize a range test.
For example, "i >= 2 && i =< 9" can be done as "(unsigned) (i - 2) <= 7".
JCODE is the logical combination of the two terms. It can be
TRUTH_ANDIF_EXPR, TRUTH_AND_EXPR, TRUTH_ORIF_EXPR, or TRUTH_OR_EXPR.
TYPE is the type of the result.
VAR is the value being tested. LO_CODE and HI_CODE are the comparison
operators comparing VAR to LO_CST and HI_CST. LO_CST is known to be no
larger than HI_CST (they may be equal).
We return the simplified tree or 0 if no optimization is possible. */
tree
range_test
(
jcode
,
type
,
lo_code
,
hi_code
,
var
,
lo_cst
,
hi_cst
)
enum
tree_code
jcode
,
lo_code
,
hi_code
;
tree
type
,
var
,
lo_cst
,
hi_cst
;
{
tree
utype
;
enum
tree_code
rcode
;
/* See if this is a range test and normalize the constant terms. */
if
(
jcode
==
TRUTH_ANDIF_EXPR
||
jcode
==
TRUTH_AND_EXPR
)
{
switch
(
lo_code
)
{
case
NE_EXPR
:
/* See if we have VAR != CST && VAR != CST+1. */
if
(
!
(
hi_code
==
NE_EXPR
&&
TREE_INT_CST_LOW
(
hi_cst
)
-
TREE_INT_CST_LOW
(
lo_cst
)
==
1
&&
tree_int_cst_equal
(
integer_one_node
,
const_binop
(
MINUS_EXPR
,
hi_cst
,
lo_cst
))))
return
0
;
rcode
=
GT_EXPR
;
break
;
case
GT_EXPR
:
case
GE_EXPR
:
if
(
hi_code
==
LT_EXPR
)
hi_cst
=
const_binop
(
MINUS_EXPR
,
hi_cst
,
integer_one_node
);
else
if
(
hi_code
!=
LE_EXPR
)
return
0
;
if
(
lo_code
==
GT_EXPR
)
lo_cst
=
const_binop
(
PLUS_EXPR
,
lo_cst
,
integer_one_node
);
/* We now have VAR >= LO_CST && VAR <= HI_CST. */
rcode
=
LE_EXPR
;
break
;
default
:
return
0
;
}
}
else
{
switch
(
lo_code
)
{
case
EQ_EXPR
:
/* See if we have VAR == CST || VAR == CST+1. */
if
(
!
(
hi_code
==
EQ_EXPR
&&
TREE_INT_CST_LOW
(
hi_cst
)
-
TREE_INT_CST_LOW
(
lo_cst
)
==
1
&&
tree_int_cst_equal
(
integer_one_node
,
const_binop
(
MINUS_EXPR
,
hi_cst
,
lo_cst
))))
return
0
;
rcode
=
LE_EXPR
;
break
;
case
LE_EXPR
:
case
LT_EXPR
:
if
(
hi_code
==
GE_EXPR
)
hi_cst
=
const_binop
(
MINUS_EXPR
,
hi_cst
,
integer_one_node
);
else
if
(
hi_code
!=
GT_EXPR
)
return
0
;
if
(
lo_code
==
LE_EXPR
)
lo_cst
=
const_binop
(
PLUS_EXPR
,
lo_cst
,
integer_one_node
);
/* We now have VAR < LO_CST || VAR > HI_CST. */
rcode
=
GT_EXPR
;
break
;
default
:
return
0
;
}
}
/* When normalizing, it is possible to both increment the smaller constant
and decrement the larger constant. See if they are still ordered. */
if
(
tree_int_cst_lt
(
lo_cst
,
hi_cst
))
return
0
;
/* The range test is invalid if subtracting the two constants results
in overflow. This can happen in traditional mode. */
if
(
!
int_fits_type_p
(
hi_cst
,
TREE_TYPE
(
var
))
||
!
int_fits_type_p
(
lo_cst
,
TREE_TYPE
(
var
)))
return
0
;
utype
=
TREE_TYPE
(
var
);
if
(
!
TREE_UNSIGNED
(
utype
))
{
utype
=
unsigned_type
(
utype
);
var
=
convert
(
utype
,
var
);
}
return
fold
(
convert
(
type
,
build
(
rcode
,
utype
,
build
(
MINUS_EXPR
,
utype
,
var
,
lo_cst
),
const_binop
(
MINUS_EXPR
,
hi_cst
,
lo_cst
))));
}
/* Try to merge two comparisons to the same innermost item.
/* Try to merge two comparisons to the same innermost item.
Also look for range tests like "ch >= '0' && ch <= '9'".
For example, if we have p->a == 2 && p->b == 4 and we can make an
For example, if we have p->a == 2 && p->b == 4 and we can make an
object large enough to span both A and B, we can do this with a comparison
object large enough to span both A and B, we can do this with a comparison
...
@@ -2355,15 +2473,44 @@ merge_component_references (code, truth_type, lhs, rhs)
...
@@ -2355,15 +2473,44 @@ merge_component_references (code, truth_type, lhs, rhs)
int
first_bit
,
end_bit
;
int
first_bit
,
end_bit
;
int
volatilep
=
0
;
int
volatilep
=
0
;
/* Start by getting the comparison codes and seeing if we may be able
/* Start by getting the comparison codes and seeing if this looks like
to do something. Then get all the parameters for each side. Fail
a range test. Fail if anything is volatile. */
if anything is volatile. */
lcode
=
TREE_CODE
(
lhs
);
lcode
=
TREE_CODE
(
lhs
);
rcode
=
TREE_CODE
(
rhs
);
rcode
=
TREE_CODE
(
rhs
);
if
(
TREE_SIDE_EFFECTS
(
lhs
)
||
TREE_SIDE_EFFECTS
(
rhs
)
||
TREE_CODE_CLASS
(
lcode
)
!=
'<'
||
TREE_CODE_CLASS
(
rcode
)
!=
'<'
)
return
0
;
if
(
TREE_CODE
(
TREE_OPERAND
(
lhs
,
1
))
==
INTEGER_CST
&&
TREE_CODE
(
TREE_OPERAND
(
rhs
,
1
))
==
INTEGER_CST
&&
operand_equal_p
(
TREE_OPERAND
(
lhs
,
0
),
TREE_OPERAND
(
rhs
,
0
),
0
))
{
if
(
tree_int_cst_lt
(
TREE_OPERAND
(
lhs
,
1
),
TREE_OPERAND
(
rhs
,
1
)))
result
=
range_test
(
code
,
truth_type
,
lcode
,
rcode
,
TREE_OPERAND
(
lhs
,
0
),
TREE_OPERAND
(
lhs
,
1
),
TREE_OPERAND
(
rhs
,
1
));
else
result
=
range_test
(
code
,
truth_type
,
rcode
,
lcode
,
TREE_OPERAND
(
lhs
,
0
),
TREE_OPERAND
(
rhs
,
1
),
TREE_OPERAND
(
lhs
,
1
));
/* If this isn't a range test, it also isn't a comparison that
can be merged. */
return
result
;
}
/* See if the comparisons can be merged. Then get all the parameters for
each side. */
if
((
lcode
!=
EQ_EXPR
&&
lcode
!=
NE_EXPR
)
if
((
lcode
!=
EQ_EXPR
&&
lcode
!=
NE_EXPR
)
||
(
rcode
!=
EQ_EXPR
&&
rcode
!=
NE_EXPR
)
||
(
rcode
!=
EQ_EXPR
&&
rcode
!=
NE_EXPR
))
||
TREE_SIDE_EFFECTS
(
lhs
)
||
TREE_SIDE_EFFECTS
(
rhs
))
return
0
;
return
0
;
ll_inner
=
decode_field_reference
(
TREE_OPERAND
(
lhs
,
0
),
ll_inner
=
decode_field_reference
(
TREE_OPERAND
(
lhs
,
0
),
...
...
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