Commit 8a61db89 by Jason Merrill Committed by Jason Merrill

PR c++/71515 - typename in partial specialization

	* pt.c (resolve_typename_type): Try to avoid calling
	currently_open_class.

From-SVN: r238696
parent 635c1074
2016-07-24 Jason Merrill <jason@redhat.com>
PR c++/71515
* pt.c (resolve_typename_type): Try to avoid calling
currently_open_class.
2016-07-23 Jason Merrill <jason@redhat.com>
PR c++/66617
......
......@@ -23678,29 +23678,26 @@ resolve_typename_type (tree type, bool only_current_p)
}
/* If we don't know what SCOPE refers to, then we cannot resolve the
TYPENAME_TYPE. */
if (TREE_CODE (scope) == TYPENAME_TYPE)
return type;
/* If the SCOPE is a template type parameter, we have no way of
resolving the name. */
if (TREE_CODE (scope) == TEMPLATE_TYPE_PARM)
return type;
/* If the SCOPE is not the current instantiation, there's no reason
to look inside it. */
if (only_current_p && !currently_open_class (scope))
if (!CLASS_TYPE_P (scope))
return type;
/* If this is a typedef, we don't want to look inside (c++/11987). */
if (typedef_variant_p (type))
return type;
/* If SCOPE isn't the template itself, it will not have a valid
TYPE_FIELDS list. */
if (CLASS_TYPE_P (scope)
&& same_type_p (scope, CLASSTYPE_PRIMARY_TEMPLATE_TYPE (scope)))
if (same_type_p (scope, CLASSTYPE_PRIMARY_TEMPLATE_TYPE (scope)))
/* scope is either the template itself or a compatible instantiation
like X<T>, so look up the name in the original template. */
scope = CLASSTYPE_PRIMARY_TEMPLATE_TYPE (scope);
else
/* scope is a partial instantiation, so we can't do the lookup or we
will lose the template arguments. */
/* We shouldn't have built a TYPENAME_TYPE with a non-dependent scope. */
gcc_checking_assert (uses_template_parms (scope));
/* If scope has no fields, it can't be a current instantiation. Check this
before currently_open_class to avoid infinite recursion (71515). */
if (!TYPE_FIELDS (scope))
return type;
/* If the SCOPE is not the current instantiation, there's no reason
to look inside it. */
if (only_current_p && !currently_open_class (scope))
return type;
/* Enter the SCOPE so that name lookup will be resolved as if we
were in the class definition. In particular, SCOPE will no
......
// PR c++/71515
template < typename, typename = int > struct A;
template < typename T > struct A < T, typename A < T >::type >
{
A < int > *a;
};
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