Commit 2dfc736c by Ian Lance Taylor

compiler: fix infinite recursion in string constant evaluation.

Fixes compilation of incorrect code:
    const f, g = g, f
    func S() []byte { return []byte(f) }

The problem was already handled for numerical constants.

Part of issue 3186 (go).

From-SVN: r186511
parent 4a101681
...@@ -2403,8 +2403,7 @@ class Const_expression : public Expression ...@@ -2403,8 +2403,7 @@ class Const_expression : public Expression
do_numeric_constant_value(Numeric_constant* nc) const; do_numeric_constant_value(Numeric_constant* nc) const;
bool bool
do_string_constant_value(std::string* val) const do_string_constant_value(std::string* val) const;
{ return this->constant_->const_value()->expr()->string_constant_value(val); }
Type* Type*
do_type(); do_type();
...@@ -2514,6 +2513,21 @@ Const_expression::do_numeric_constant_value(Numeric_constant* nc) const ...@@ -2514,6 +2513,21 @@ Const_expression::do_numeric_constant_value(Numeric_constant* nc) const
return r; return r;
} }
bool
Const_expression::do_string_constant_value(std::string* val) const
{
if (this->seen_)
return false;
Expression* e = this->constant_->const_value()->expr();
this->seen_ = true;
bool ok = e->string_constant_value(val);
this->seen_ = false;
return ok;
}
// Return the type of the const reference. // Return the type of the const reference.
Type* Type*
......
Markdown is supported
0% or
You are about to add 0 people to the discussion. Proceed with caution.
Finish editing this message first!
Please register or to comment